Why is head to tail addition
favored?
The mechanical strength of a polymer
material is dependent on its average molecular weight. The higher it is, the stronger the material
will be. Which termination step (combination
or disproportionation) favors strong materials?
Formation of Long Branches in
Polymers


Polymerization
continues from
this
point.
b-Cleavage


a,b-unsaturated ketone
b-cleavage
reaction

reverse of polymerization
: depolymerization (DG = DH – TDS)
Polymerization
important at lower temperatures.
Depolymerization
important at higher temperatures.
The temperature at
which depolymerization becomes more important and the polymer breaks down is
known as the ceiling temperature.
Autooxidation

ether diethyl ether tetrahydrofuran
![]()

hydroperoxides peroxides
Further
reactions occur to various products.
Mechanism
Initiation
1. A radical R’. is generated
somehow.


resonance
stabilized, more stable

net stabilization

less stable

Termination

![]()
Autooxidation is a
slow reaction that results in a change in the structure of a molecule. If this molecule is used in some application,
such structural changes generally mean that the molecule will not fulfill its
function. Further autooxidation can
lead to total degradation. These
reactions are partially responsible for the deterioration of food, plastics,
paint, dyes, etc.
Ethers: store in
dark, preferably cool, store < 1 yr., treat with solution of Fe+2
salts (FeSO4)
Antioxidants
(a.k.a. inhibitor) react with R’. faster than R-H, R-O-R, etc.

BHT BHA butylated hydroxyanisole
butylated
hydroxytoluene

Vitamin E (a-tocopherol)

What 2 factors lead
to this being a very unreactive radical that will inhibit further reaction?
Atherosclerosis
In atherosclerosis,
an autooxidation reaction occurs. Molecules
(L-H) in low density lipoprotein particles (LDL) undergo reactions with oxygen.
Initiation

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Propagation
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Vitamin E (a-tocopherol) is
believed to act as an inhibitor, but the mechanism is not clear.
V. W. Bowry, K. U.
Ingold, Accounts of Chemical Research,
1999, Vol. 32, p. 27
Allylic Halogenation
(Bromination)

NBS, N-bromosuccinimide succinimide
Markovnikov Addition

Anti-Markovnikov Addition

So far, 5 different
reactions have been covered that add one or more Br atoms to molecules.


(Some free radical
initiator present)




Mechanism of Allylic Bromination
Initiation

Propagation

H-Br undergoes a rapid
reaction with NBS and will not have a chance to react with any radicals
present.

Br-Br is generated at
a very low concentration.

The alkene
concentration is kept low.
Polymerization does not occur.
H-Br reacts with NBS
before radicals can. No addition of
H-Br occurs.

resonance
stabilized, most favorable
vinyl
radical, less stable than allylic radical
2° radical, but not resonance stabilized

This pathway is not
likely because the bromine concentration is too low. The concentration of all other likely reactants are also
low. Most likely pathway will be
reverse reaction.

The first step is not
reversible because NBS removes H-Br from the reaction mixture. Although the reaction of the radical and Br2
is slow because of their low concentrations, it is the only likely pathway
remaining.
Chapter 11 Conjugated Dienes and
the Allyl System:
2p Orbitals in Conjugation
- Large differences in reactivity of
C=C in different molecular structures
- How molecules absorb and emit
light and why substances have color
- Biochemical process of vision
- Biosynthesis of steroids }
terpenes and terpenoids
- Conducting polymers (molecular
wires and polymer based LED’s)
Conjugated
systems: structures having alternating single and double bonds
e.g. 1,3-butadiene ![]()
To some extent, the p
orbitals overlap in a sequential manner

unconjugated
or nonconjugated structures contain
“isolated” double bonds
e.g. 1,4-pentadiene ![]()
Other conjugated
compounds
1,3,5-hexatriene a,b-unsaturated benzene
carbonyl



allene ketene
Examples of molecules
with cumulated double bonds.


Conjugated anions, cations,
and radicals are more stable than the corresponding nonconjugated species. The charge and electrons are delocalized
over more than 1 atom. This is often
represented by resonance structures and can be explained through molecular
orbital theory.
![]()

Somewhat more stable
than corresponding nonconjugated compounds.

Heats of Hydrogenation
|
|
DH° kcal/mole |
|
|
-57.1 |
|
|
-60.8 |
|
|
-60.5 |
Hydrogenation of
1,3-butadiene is ~
4 kcal/mole less exothermic. This means
that it is ~
4 kcal/mole more stable.

appears to have a
small amount of p
bond character
¯
¬ looks like normal double bond
On average C-C : 1.54 A
C=C : 1.33 A
shorter than single bond but longer than
a double bond, indicates some but
not complete p
bond character

|
|
|
|
nearly free
rotation E barrier = 2.9
kcal/mole |
no bond rotation at
RT E barrier » 66 kcal/mole |
|
|
|
|
no bond rotation E barrier similar
to other p
bonds |
rotation occurs E barrier » 4-5 kcal/mole
indicates some p
character |
2 conformations possible, both
overall planar
|
|
|
|
s-cis s-cis-1,3-butadiene |
s-tran s-trans-1,3-butadie |
Which conformation
appears to be more stable?
Butadiene

Would forms A, C, and
D contribute significantly?
Molecular Orbitals of
1,3-Butadiene
s MO’s are much lower in E than p MO’s
s* MO’s are much
higher in E than p*
MO’s
p MO will be HOMO
p* MO will be LUMO

p orbital,
1 node (region of 0 electron density separating regions of high electron density
p MO, 1 node, 1 bonding interaction (lobes match)
p* MO, 2 nodes, 1 new node relative to lowest E MO, 1
antibonding interaction
(lobes opposite)
To determine the
relative energies of the MO’s, the following must be compared:
a. the # of new nodes
relative to the lowest E MO
(lower # new nodes, lower E)
b. the net # of bonding/antibonding
interactions
(more bonding or less
antibonding, lower E)
Ethylene p MO lower in E than p* MO
0 new nodes 1 new node
1 bonding int. 0 bonding int.
0 antibonding int. 1 antibonding int.
1,3-Butadiene

Both (pe1 + pe2) and (pe1 - pe2) are bonding MO’s
and are energetically stabilizing.
In (pe1 + pe2) there is a
bonding interaction between C2 and C3.
In (pe1 - pe2) there is an
antibonding interaction between C2 and C3.
They should cancel
out except that since (pe1 + pe2) is lower in energy, there will be a small net bonding
interaction giving C2-C3 some p bond character.

photon E = hn = hc/l where E = energy
h
= Planck’s constant
n = frequency (1/s)
l = wavelength (nm)
If E photon = DE B-C,
then there is a probability that the photon will be absorbed by the molecule
resulting in an electron being promoted from B to C*. This is called an
electronic transition.
Commonly Observed Transitions in Organic Molecules
s - s*
p - p*
n - s*
n - p*
n - s* and n - p* occur when a molecule
has nonbonding or lone pair electrons, e.g. allyl carbanion
![]()

e.g. n - p*